[{"data":1,"prerenderedAt":-1},["ShallowReactive",2],{"kakomon-q-2024-ippan-50":3},{"slug":4,"exam_year":5,"exam_round":6,"section":7,"section_code":8,"number":9,"body":10,"choices":11,"correct_indices":28,"explanation":29,"has_explanation":24,"tags":30},"2024-ippan-50",2024,2,"一般","ippan",50,"10 ％塩化ベンザルコニウム消毒液を希釈して0.05 ％液を500 mL 調整するのに必要 な原液量はどれか。",[12,16,18,21,25],{"index":13,"body":14,"is_correct":15},1,"1.0 mL",false,{"index":6,"body":17,"is_correct":15},"1.5 mL",{"index":19,"body":20,"is_correct":15},3,"2.0 mL",{"index":22,"body":23,"is_correct":24},4,"2.5 mL",true,{"index":26,"body":27,"is_correct":15},5,"3.0 mL",[22],"正答は4（2.5 mL）。必要な原液量＝作りたい濃度×量÷原液濃度＝0.05%×500 mL÷10%＝2.5 mL（これを水で500 mLにメスアップする）。計算式に当てはめると 500×（0.05／10）＝2.5 mL。1の1.0・2の1.5・3の2.0・5の3.0 mLはいずれも計算が合わない。よって2.5 mL。**覚え方**: 希釈は『原液量＝作る濃度×作る量÷原液濃度』。濃度を1\u002F200にするなら原液は全量の1\u002F200。",null]